Problem · Open · Mathematics
The Collatz Conjecture
Listen
A two-line rule any child can run. Every starting number anyone has tried still falls into 4, 2, 1.
01 · History
Halve it, triple it, and wait for the storm to land
Pick any positive whole number. If it is even, halve it. If it is odd, triple it and add one. Then do it again. And again. The numbers rise like hailstones in an updraft, then fall. Every path anyone has tried lands in the little loop 4, 2, 1. Nobody has proved that every starting number must.
Lothar Collatz started passing the rule around in the 1930s, while he was still a student listening to Edmund Landau and Issai Schur. He never published a grand paper on it. He just kept asking what the iteration does. In 1950 he was still handing the question to people at the International Congress of Mathematicians. The problem picked up other names the way a rumor does: Kakutani’s problem, Ulam’s problem, the Syracuse problem, hailstone numbers, the 3n+1 problem. Same itch under every label.
Paul Erdős put money on the table for progress. Jeffrey Lagarias later recorded him saying mathematics is not yet ready for such problems. The remark travels through those surveys, not through a filmed speech. The meaning is blunt enough either way. A child can run the rule. The proof still refuses to show up.
The numbers really do look like hail. Start at 7 and you climb to 52, then later fall through 16, 8, 4, 2, 1. Start at 27 and the storm lasts 111 steps, with a peak at 9,232. Then that same 4-2-1 trap. The attracting cycle is tiny. The climb can be huge. The conjecture says every positive integer is a hailstone that eventually hits the ground.
A short hailstorm
Start at 7. Watch the values climb, then drop into 4, 2, 1.
- Steps to 1
- 16
- Peak
- 52
02 · Exact statement
The claim in one sentence
Collatz conjecture
Start with any positive integer n. If it is even, replace it by n/2. If it is odd, replace it by 3n+1. Repeat. Every such sequence eventually reaches the cycle 4 → 2 → 1.
In plain language: no matter which positive whole number you start with, repeated halving of evens and the 3n+1 move on odds will, after finitely many steps, arrive at 1 and then loop 4, 2, 1 forever. The conjecture does not ask how high a path may climb. It asks whether every path comes down.
03 · Where it stands
Checked past two to the seventy-first. Still no general proof.
Computers have been throwing hailstones for decades. Oliveira e Silva and later Roosendaal pushed the verified range past 10^18, then past 10^20. Barina’s distributed project, published in 2025, checked every start below 2^71. No counterexample appeared. A finite list, even a monstrous one, still leaves infinitely many unchecked integers.
Partial theorems have more texture than the machine search. Terras, in 1976, proved that almost all starting values have a finite stopping time: they eventually go strictly below where they began. Allouche and later Korec pushed those “drop below a power of the start” results further. Krasikov and Lagarias gave density lower bounds on how many starts below a large X are already known to reach 1. In 2019 Tao proved that almost all orbits, measured by logarithmic density, attain values that are almost bounded: smaller than any function that drifts slowly to infinity. None of that is a proof for every n.
Jeffrey Lagarias has been the problem’s long-haul cartographer since the 1980s: surveys, an annotated bibliography, and a collected volume that still orients anyone who wants the literature straight. The honest status line is the same one he has been writing for years. The conjecture looks true. Present methods do not reach a general proof.
- Formal status
- Open. Outside the Clay Millennium list, and still one of the most famous unsolved iteration problems.
- Machine checks
- David Barina’s 2025 verification covers every starting value below 2^71. That is evidence. The finish line is still a proof.
- Almost-all theorems
- Riho Terras showed that almost all integers (natural density) eventually drop below their start. Terence Tao (2019) showed that almost all orbits, in logarithmic density, get almost bounded.
- What remains missing
- A proof that every positive integer reaches 1, or a single start that escapes the 4-2-1 cycle.
What would count as solved
The finish line, in plain language
A solution is a proof that every positive integer eventually reaches the cycle 4, 2, 1, or a counterexample: a starting value that diverges, or that enters some other cycle. Checking finitely many starts, even past 2^71, leaves the claim open.
- Prove that the orbit of every positive integer reaches 1 (and therefore the 4-2-1 cycle), or exhibit a start that never does.
- A finite verification, a density theorem about almost all starts, and a bound on how small most orbits get are progress. They do not settle every starting number.
- The argument must be a conventional mathematical proof that experts can check.
04 · Visualizations
Watch a hailstone rise, fall, and land in 4-2-1
The toy below runs the actual rule. Pick a start, play or scrub the steps, and keep an eye on the peak. Then compare a few famous starting values. 27 is the loud one in this neighborhood.
Hailstone trajectory
Pick a start, then walk the rule. The path rises and falls until it hits the 4-2-1 trap.
- Now
- 27
- Steps so far
- 0
- Steps to 1
- 111
- Peak
- 9,232
A few starts, side by side
Same rule. Wildly different storms. 27 is the loud one in this neighborhood.
| Start | Steps to 1 | Peak |
|---|---|---|
| 8 | 16 | |
| 16 | 52 | |
| 17 | 160 | |
| 111 | 9,232 | |
| 106 | 9,232 | |
| 109 | 9,232 | |
| 104 | 9,232 |
05 · Impact
Why a playground rule still measures the integers
If the conjecture is true, the positive integers have a hidden drainage system: every start, after some weather, empties into one tiny cycle. A proof would lock that drainage down. A counterexample would be a single integer whose orbit flies off, or a second cycle nobody has found among the positives.
The hunt has already paid rent. The 3n+1 map sits next to questions about how well powers of two approximate powers of three, about ergodic motion on 2-adic integers, and about generalizations that Conway showed can encode undecidable problems. Those cousins explain the dread. A rule this small can hide weather that current proof technology cannot forecast.
That is why Erdős’s readiness remark still gets quoted. The Collatz conjecture is a measuring stick for how much structure we can actually see in the simplest iteration on the whole numbers. The hailstones keep falling in every experiment. The theorem that says they must is still missing.
Dive deeper
Video
The Simplest Math Problem No One Can Solve
Veritasium ↗
A public walk through hailstone numbers, the 4-2-1 trap, and why a child-size rule still resists a proof.
Reading
The 3x+1 Problem and Its Generalizations
Jeffrey C. Lagarias (American Mathematical Monthly) ↗
The 1985 survey that mapped the problem, recorded Erdős’s readiness remark, and still orients the literature.
Reading
Almost all orbits of the Collatz map attain almost bounded values
Terence Tao (Forum of Mathematics, Pi) ↗
The 2019 theorem that almost all orbits, in logarithmic density, get arbitrarily close to bounded.